%BIT_IS_CLR

Evaluate if a bit is clear

WSupported on Windows
USupported on Unix
VSupported on OpenVMS
NSupported in Synergy .NET
status = %BIT_IS_CLR(bit, value)

Return value

status

One of the following values: (n)

1 = The bit is clear.

0 = The bit is set.

Arguments

bit

The number of the bit to be evaluated. (n)

value

The value whose binary representation contains the bit to be evaluated. (n)

Discussion

%BIT_IS_CLR evaluates a bit value in the binary representation of a value.

Bit numbering is zero-based. Bit can be 0 through 63 (or 31 on 32-bit systems), corresponding to values 1 through 8000000000000000 (hexadecimal).

Tip

We recommend using bitwise Boolean operators rather than the %BIT_IS_CLR and %BIT_IS_SET functions.

See also

Bitwise operations

Examples

The following example evaluates bit number 2 in the binary representation of 20:

%bit_is_clr(2,20)

Since the binary representation of 20 is 10100, and bit number 2 is actually the third bit from the right, this call to %BIT_IS_CLR returns a value of zero.

The example below translates bit flags and displays their values to the terminal.

subroutine show_bflags”
    a_bit_flags          ,n             ;Bit positions
.define PUBLIC_BIT       ,4
.define DOMESTIC_BIT     ,5
.define LESS50_BIT       ,6
.define VMAIL_BIT        ,7
proc
    xcall showit("Public company?", 
  &       %bit_is_clr(PUBLIC_BIT, a_bit_flags))
    xcall showit("Domestic sales only?", 
  &       %bit_is_clr(DOMESTIC_BIT, a_bit_flags))
    xcall showit("Less than 50 employees?", 
  &       %bit_is_clr(LESS50_BIT, a_bit_flags))
    xcall showit("Voice mail system?", 
  &       %bit_is_clr(VMAIL_BIT, a_bit_flags))
    return
endsubroutine
subroutine showit
    a_txt       ,a              ;Text to display
    a_set       ,n              ;1 = set, 0 = not set
record
    yn          ,a1             ;Y or N
proc
    if (a_set) then 
      yn = 'N'
    else
      yn = 'Y'
    display(TTCHN, a_txt, " (Y/N) ", yn)
    return
endsubroutine